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Thread: Question about FlexLM license

  1. #1
    skew
    Guest

    Question about FlexLM license

    I have C compiler for mips cpu.
    The name is Diab C compiler.

    I tried to generate a license data file.
    At last, I generator a good working license data file.

    But...
    I have two versions of that compiler.
    v4.1a and v4.3f

    v4.1a use lmgr325c.dll and v4.3f use lmgr326b.dll
    I successfully generate license file for v4.1a with FlexLM SDK 6.1f
    But I failed generate license file for v4.1a with FlexLM SDK 5.12b

    I don't understand why I fail.

    could you know about this?

    thanks.


    ps:
    Can I upload test environment ?
    (sample c code, batch file for compile, minimizied c compiler)
    It is small. (966,590 bytes)

    My company bought this compiler.
    So, I have real license file.
    I promise that I have read the FAQ and tried to use the Search to answer my question.

  2. #2
    Kythen
    Guest
    There is a special number in each major FlexLM version (ie, 5.12, 6.x, 7.0, etc.). In order to make licenses for older FlexLM versions, you have to patch in the correct number in your license generator. There is an essay that tells you exactly how to do in on Tsehp's main site.

    HTH!

    Kythen
    I promise that I have read the FAQ and tried to use the Search to answer my question.

  3. #3
    skew
    Guest
    Oh, I'm sorry.

    my essay was something wrong. (misstyping. )

    I successfully generate license file for v4.3f with FlexLM SDK 6.1f
    But I failed generate license file for v4.1a with FlexLM SDK 5.12b

    v4.1a use lmgr325c.dll
    and I work with FlexLM SDK 5.12b.

    I don't understand why I fail.

    thanks
    I promise that I have read the FAQ and tried to use the Search to answer my question.

  4. #4
    tom_324
    Guest
    FlexLM license is depending upon seeds only, so you can generate 5.12 license with 6.1 SDK. Just check lmcrypt. Hint : lmcrypt -verfmt

    Tom
    I promise that I have read the FAQ and tried to use the Search to answer my question.

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